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X^2+19X-97=0
a = 1; b = 19; c = -97;
Δ = b2-4ac
Δ = 192-4·1·(-97)
Δ = 749
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-\sqrt{749}}{2*1}=\frac{-19-\sqrt{749}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+\sqrt{749}}{2*1}=\frac{-19+\sqrt{749}}{2} $
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